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・ Vitali Petrushin
・ Vitali Pinyaskin
・ Vitali Polevikov
・ Vitali Prokhorov
・ Vitali Proshkin
・ Vitali Pugin
・ Vitali Pushkar
・ Vitali Pyanchenko
・ Vitali Rodionov
・ Vitali Romanenko
・ Vitali Safronov
・ Vitali Samoilov
・ Vitali Sazonets
・ Vitali Seletskiy
・ Vitali Semakin
Vitali set
・ Vitali Shakhov
・ Vitali Shipilov
・ Vitali Silicki
・ Vitali Silitski
・ Vitali Sitnikov
・ Vitali Smirnov
・ Vitali Smolyaninov
・ Vitali Stezhko
・ Vitali Streltsov
・ Vitali Tajbert
・ Vitali Tasenko
・ Vitali Teleš
・ Vitali theorem
・ Vitali Tikhonov


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Vitali set : ウィキペディア英語版
Vitali set
In mathematics, a Vitali set is an elementary example of a set of real numbers that is not Lebesgue measurable, found by Giuseppe Vitali. The Vitali theorem is the existence theorem that there are such sets. There are uncountably many Vitali sets, and their existence is proven on the assumption of the axiom of choice.
== Measurable sets ==
Certain sets have a definite 'length' or 'mass'. For instance, the interval (1 ) is deemed to have length 1; more generally, an interval (''b'' ), ''a'' ≤ ''b'', is deemed to have length ''b''−''a''. If we think of such intervals as metal rods with uniform density, they likewise have well-defined masses. The set (1 ) ∪ (3 ) is composed of two intervals of length one, so we take its total length to be 2. In terms of mass, we have two rods of mass 1, so the total mass is 2.
There is a natural question here: if E is an arbitrary subset of the real line, does it have a 'mass' or 'total length'? As an example, we might ask what is the mass of the set of rational numbers, given that the mass of the interval (1 ) is 1. The rationals are dense in the reals, so any non negative value may appear reasonable.
However the closest generalization to mass is sigma additivity, which gives rise to the Lebesgue measure. It assigns a measure of ''b'' − ''a'' to the interval (''b'' ), but will assign a measure of 0 to the set of rational numbers because it is countable. Any set which has a well-defined Lebesgue measure is said to be "measurable", but the construction of the Lebesgue measure (for instance using Carathéodory's extension theorem) does not make it obvious whether non-measurable sets exist. The answer to that question involves the axiom of choice.

抄文引用元・出典: フリー百科事典『 ウィキペディア(Wikipedia)
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